Question

integrate

Answer 1

\[\frac{ x^{2}-\sqrt{x} }{ x }\] integrate

Answer 2

express this as
\[\frac{ x^2 }{ x } - \frac{ \sqrt(x )}{ x }\]

Answer 3

then u will get
\[x- \frac{ 1 }{ \sqrt(x) }\]
in order to solve further
remember
\[\int\limits_{}^{}x^n dx = \frac{ x^{n+1} }{ n+1 }\]

Answer 4

\[\huge \int\limits [\frac{x^2}{x} -\frac{\sqrt x}{x} ]dx = \int\limits [x -\frac{1}{\sqrt x} ]dx \]
\[\huge = \int\limits [x -\frac{1}{x^{\frac{1}{2}}} ]dx \]
\[\huge = \int\limits x dx - \int\limits {x^{-\frac{1}{2}}} dx = \frac {x^2}{2} - 2{x^{\frac{1}{2} }} +c \]
\[\huge = \frac {x^2}{2} - 2 \sqrt x +c\]

@supersolver