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Chemistry 18 Online
OpenStudy (anonymous):

When aqueous solutions of potassium carbonate and cobalt(II) iodide are combined, solid cobalt(II) carbonate and a solution of potassium iodide are formed. The net ionic equation for this reaction is:

OpenStudy (aaronq):

first write the complete reaction, then eliminate the ions that are not involved in the reaction occurring (i.e. forming precipitate).

OpenStudy (anonymous):

not involved? you mean the soluble ones

OpenStudy (aaronq):

yep, the ones that are not involved in making the precipitate.

OpenStudy (anonymous):

okay hold on im writing it out

OpenStudy (anonymous):

would it be CO3^2-+CO^2+> CO2+ +CO3^2-

OpenStudy (aaronq):

nope. where are the parts that form the precipitate?

OpenStudy (anonymous):

2k+ + CO3^2- +CO^2+ +2I- > CoCO3 +K+ +I-

OpenStudy (aaronq):

so don't show \(K^+\) or \(I^-\), otherwise it's good.

OpenStudy (anonymous):

so the 2k+ is okay also

OpenStudy (aaronq):

nope, don't show those ions at all, because they're spectator ions

OpenStudy (anonymous):

okay so CO3^2- +Co^2+ > CoCO3 (S)

OpenStudy (anonymous):

thas my answer?

OpenStudy (aaronq):

yep, thats it

OpenStudy (anonymous):

YES ! THANK YOU

OpenStudy (anonymous):

so like before there was 2k in one side and in the other just k..it doesnt matter if there identical there eliminated because they fall under the solubility rule right?

OpenStudy (aaronq):

we'll technically they should be balanced, so K should appear the same amount of times. But you're correct that they're eliminated because of their solubility.

OpenStudy (anonymous):

okay i have one more question could you wait a little bit for me?

OpenStudy (aaronq):

sure, post it and i'll come back to take a look at it.

OpenStudy (anonymous):

When aqueous solutions of sodium acetate and hydrobromic acid are mixed, an aqueous solution of sodium bromide and acetic acid results. Write the net ionic equation for the reaction.

OpenStudy (anonymous):

so i have NaC2H302- + H+ > H- + C2H402

OpenStudy (aaronq):

close. you have too many H's. |dw:1393723061672:dw|

OpenStudy (aaronq):

and while acetate is negatively charged, the sodium ion counteracts that charge and thus is neutral.

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