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Chemistry 18 Online
OpenStudy (amtran_bus):

Chemical equilibrium?

OpenStudy (amtran_bus):

A+2B-->C (all gases) The initial amounts of reactants placed into a 5L vessel were 1 mol A and 1.8 mol B. After the reaction reached equilibrium, 1 mole of B was found. Find Kc.

OpenStudy (amtran_bus):

I need to make an ICE table but I need help on this.

OpenStudy (aaronq):

A B C I 1/5 1.8/5 0 C -x -2x +x E 1/5-x 1.8/5-2x x does that make sense to you?

OpenStudy (amtran_bus):

Yes. Why do you go ahead and divide by 5 and not wait until later?

OpenStudy (aaronq):

what do you mean later? equilibrium expressions are in terms of concentration

OpenStudy (amtran_bus):

I had a homework problem that was like this and it waited...

OpenStudy (amtran_bus):

In steps 1-5.

OpenStudy (aaronq):

oh, we'll it doesn't really matter when you do it. It works out to the same thing (as long as you do it before you plug into the eq. expression).

OpenStudy (amtran_bus):

Ohh ok. Thanks! I really needed that.

OpenStudy (aaronq):

no problem, glad you got that clarified !

OpenStudy (amtran_bus):

How would I finish the rest of the problem? That is, solve for X? Do I need to do the product over reactant thing?

OpenStudy (amtran_bus):

I know the final of B...it is given.

OpenStudy (amtran_bus):

@aaronq

OpenStudy (aaronq):

well since the give you the final moles of B, you can use 1.8/5-2x=1/5 to find x, note that i divided the number of moles by the volume because i did that earlier.

OpenStudy (amtran_bus):

Ok, so that is .08.

OpenStudy (amtran_bus):

Does that mean I can use .08 for C and plug it in the 1/5 -x for A?

OpenStudy (aaronq):

yes

OpenStudy (amtran_bus):

Ok. I understand now. Thank you.

OpenStudy (amtran_bus):

The answer is 17.

OpenStudy (aaronq):

no problem ! glad i could help

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