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x^3 + 64 = 0. find the imaginary number by factoring??
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-4 is not an imaginary number so that cannot be the answer.
Factor x^3+64
I'll get you started: \[x^3+64=(x+4)(x^2 \]
\[a^3+b^3=\left( a+b \right)\left( a^2-ab+b^2 \right)\]
Now you finish the factoring.
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im a bit confused where you got x^3 + 64?? @Mertsj
oh wow i needed to look at the problem im an idiot aha
That is the problem you posted.
You must have studied factoring and specifically the factoring of the sum of two cubes. Use that knowledge to factor x^3+64
i must have i just do not remember. math is just very difficult for me
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Ok. Watch this: |dw:1393719357803:dw|
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