Question

An experiment consist of rolling two fair number cubes. Find each outcomes.

P(rolling a total less then 2)????

Answer 1

P(sum < 2)=0

Answer 2

How do I do that

Answer 3

Are u there???

Answer 4

sample space or exhaustive events are 11,12,13,14,15,16,
21,22,23,24,25,26,
............................,
.............................,
.............................,
61,62,63,64,65,66.
Total no. of exhaustive events=6*3=36
smallest sum=1+1=2
largest sum=6+6=12
we do not get sum <0
no. of favourable events=0
\[Required~ probability=\frac{ 0 }{ 36 }=0\]

Answer 5

correction 6*6=36

Answer 6

Ok what if it says p(rolling a total of 9) how do I do this
Is it like 9/36=1/4

Answer 7

favourable events=36,45,54,63
no. of favourable events=4
P=4/36=1/9

Answer 8

Why 4 doe?

Answer 9

I am so confused

Answer 10

you want sum=9
they are only four as i have shown above in the table.

Answer 11

we have to find the numbers of favourable events i.e.,sum =9

Answer 12

you got it .

Answer 13

Yeah thanks

Answer 14

But
How did u got 36.45.54.63
And why only those number
And how u got that