Proof for parallelogram (fill in the blanks) Given PQRS is a parallelogram prove PR and QS bisect each other at T
1) PQRS is a parallelogram 1) 2)PQ is parallel to RS 2)definition for parallelogram 3)m<1=m<3 m<2=m<4 3) 4)PQ=RS 4)opposite sides of a parallelogram are congruent 5)triangle PQT= triangle RST 5) 6)PT-RT 6) 7) 7)definiton of a bisector
Do you know the first answer?
no
The second line says "Given PQRS is a parallelogram" so reason 1) is simply "given"
as for 3), I would need to see a pic of it to know where angles 1, 2, 3, 4 are
|dw:1393906474674:dw|
thanks
any ideas why angle 1 = angle 3? and why angle 2 = angle 4? hint: look at how PQ is parallel to ST
because opposite angles are congruent in a parallelogram
not quite
what kind of angles are 1 and 3?
yeah i cant find that anywhere in my notes
If we have 2 parallel lines |dw:1393908177175:dw|
then we cut them with a transversal |dw:1393908193350:dw|
then the alternate interior angles |dw:1393908208113:dw| will be congruent
So that's why m<1=m<3 and m<2=m<4
ok so it would just be 3) alternate interior angles
correct
what about for 5 both triangles are congruent which means
how do we know they are congruent?
because in the given column is says triangle PQT= triangle RST
but what is the reason?
how do we justify that?
the triangles have 3 sets of congruent angles and sides
look back at the proof, you'll see that not all 3 sides are used to prove the two triangles are congruent
then just the angles? because we know what the angles are since they are congruent to each other
we have 2 angles, and a side between them, so instead of SSS we use ASA
m<1 = m<3 is one pair of angles m<2 = m<4 is the other pair PQ=RS is the set of sides sandwiched between the angles
so 5) would be just ASA
yep ASA property of congruence
and would 6) be SSS because PT and RT are sides as well as QT and ST
no, if you know two triangles are congruent, what can you say about the corresponding pieces?
it's not SSS
what about CPCTC
yep it's CPCTC
and would 7) be PR and QS bisect each other at T
the last statement is ALWAYS the thing you want to prove, so you are correct
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