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To produce 3.37 liters of a 1.12 M solution of magnesium nitrate, how many grams of magnesium nitrate must be dissolved?
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I am a little busy, sorry but I think @abb0t and @aaronq may help you out. They are one of the best Chemistry Experts on OpenStudy! Good Luck
@abb0t ?
Same thing. Molar mass times molarity times number of liters.
148.32 \(\sf \frac{g}{mol}\) \(\times\) \(\sf \frac{1.12~mol}{L}\) \(\times ~\sf 3.37~L\) = grams of Mg(NO\(\sf_3\))\( _2\)
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