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Mathematics 14 Online
OpenStudy (anonymous):

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OpenStudy (anonymous):

consider vn=1/n^(1/2) \[\lim_{n \rightarrow \infty} \frac{ an }{ bn }=\lim_{n \rightarrow \infty}\frac{n ^{\frac{ 1 }{ 2 }}( n+2)^2 }{ n^3 }*\frac{ n ^{\frac{ 1 }{ 2 }} }{ 1 }\] \[=\lim_{n \rightarrow \infty}\frac{ n ^{\left( \frac{ 1 }{ 2 }+\frac{ 1 }{ 2 } \right)n^2\left( 1+\frac{ 2 }{ n } \right)^{2}} }{ n^3 }\] \[\lim_{n \rightarrow \infty}\frac{ n^3\left( 1+\frac{ 2 }{ n } \right)^2 }{ n^3 }=1+0=1\] which is finite,hence they behave alike. compare bn with\[n ^{\frac{ 1 }{ p }},p=\frac{ 1 }{ 2 }<1~ hence ~ series ?\]

OpenStudy (anonymous):

correction\[\frac{ 1 }{ n^p }\]

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