Question

\int_0^π/2 {cos x dx/(1+sin^2x)} :/

Answer 1

Let sin^2 x = y
and then solve

Answer 2

D/DX SIN^2X=?

Answer 3

y = sin x would be a better choice

Answer 4

@hartnn yeah i agree

Answer 5

Isn't there a 2 coefficient?

Answer 6

oh that is pi/2 upper limit, never mind

Answer 7

d/dx sin^2x = 2(sinx)cosx dx d/dx sinx = cosx dx

u = sin x
du = cos x dx

integral from 0 to 2pi 1 / (1+u^2) du

Answer 8

u get it??

Answer 9

;)

Answer 10

the limits would change

Answer 11

thak u !!!

Answer 12

hint it's tan^-1 x (antidreivativee)

and yeah I messed up the limits will change

Answer 13

u = sin x
when x = 0, u= 0
when x= pi/2, u= 1
new limits for u
0 to 1

Answer 14

@hartnn ty

Answer 15

give me a metal plz

Answer 16

ty :)