I need to find the limit as x goes to 9. I must use factoring. How can I factor?
((x^(3/2))-27) / x-9

Question

ganeshie8 · Answer

use a^3-b^3 formula for numerator

alekos · Answer

not sure if that's going to do the trick
we get on the top line (sqrtx -3)(x+3sqrtx +9)

ganeshie8 · Answer

bottom also we can factor : $ x- 9 =  (\sqrt{x})^2 - 3^2$

alekos · Answer

yes of course!

alekos · Answer

over to you ham and bones

anonymous · Answer

I don't think this solves the problem. I am trying to find the limit as x goes to 9. If you put in 9 for x, the denominator is still 0 or undefined. Something must be cancelled off so you can plug 9 into for x and solve.

alekos · Answer

Yes it does.

Top line (sqrtx -3)(x+3sqrtx+9)
Bottom line (sqrtx+3)(sqrtx-3)