Question

derivative 3sec(x)

Answer 1

Start with the derivative of sec x. Find that, and then multiply the result by 3.

Note that sec x is one of the 6 trig functions whose derivatives we need to know and know well.

\[\frac{ d }{ dx }\sin x = \cos x\]
\[\frac{ d }{ dx }\cos x = -sin x\]
and so on. Please look up the derivative of sec x.

Answer 2

sec(x) tan(x)
therefore 3sec(x) = 3 sec(x) tan(x) ??

Answer 3

I'd prefer that you type out the whole derivative:\[\frac{ d }{ dx }\sec x = \sec x*\tan x.\]

You have the derivative correct, but your label (3sec x) is not correct. Please write:

Answer 4

\[\frac{ d }{ dx }3\sec x=3\sec x*\tan x\]

Answer 5

ok thank you for your help :)

Answer 6

sorry to be picky, but this labeling is important.
You'd not be able to prove that 3sec(x) = 3 sec(x) tan(x); instead, it's\[\frac{ d }{ dx }3\sec x =3\sec x \tan x\]that is correct.

Nice working with you. Good luck!

Answer 7

also would 5tan(t) equal 5sec^2(t) ??

Answer 8

sorry 5tan(t) = dy/dt 5sec^2(t)

Answer 9

James, what you've typewritten here is does not represent the math problem that you're solving, because you have not indicated that you're taking the derivative. This is the same thing I mentioned earlier.

5tan(t) = dy/dt 5sec^2(t) is not correct; you must include the derivative operator, d /dt, in front of that 5tan t.



Use Equation Editor:\[\frac{ d }{ dt }5\tan t\] or use Draw: