Question

plz, need som help :)
i will love +fan + medal :P
let a point A of mass M be fixed & \(p_0\) a point , let a particle B of mass m be free in the space , A attracts B according to newtons law of gravitation ,
the magnitude \(g_1\)gravitation for portials to
\(\frac{1}{r^2}\), where r is the distance between A&B ,Force=F
\(|F|=\frac{c}{r^2}\)
show that
\(F=|F|(\frac{-1}{r}r')=\frac{-c}{r^3}r'\)
were \(r'=[x-x_0,y-y_0,z-z_0]\)
\(p=(x,y,z)\)
\(p_0=(x_0,y_0,z_0)\)

Answer 1

\(\large \overrightarrow{F} = |F| \frac{-1}{r}\overrightarrow{r}\)

Answer 2

like that ?

Answer 3

yes

Answer 4

@ganeshie8 then ?

Answer 5

Newton's law says, the direction of force is radially towards the center of M

Answer 6

so thats gives \(\|F|=\frac{c}{r^2}\)