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Be f(x)=e^3x-1 evaluate for f(Ln2)
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replace the x in the equation by ln2
now you have \[f(\ln2)=e ^{3\ln2}-1\]
I did it. Thats all?
Tyvm Esamalla but why -1 is now on the bottom
is your equation \[e ^{3x}-1 or e ^{3x-1}\]
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\[f(\ln2)=e ^{3\ln2-1}\]
this is the ans if your equation is the second
\[f(x)=e ^{3x-1}=e ^{3x}e ^{-1}=\frac{ e ^{3x} }{ e }\] \[f \left( \ln 2 \right)=\frac{ e ^{3\ln 2} }{e }=\frac{e ^{\ln 2^{3}} }{ e }=\frac{ 8 }{e }\]
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