Question

191=2x-3(7x+6)

Answer 1

To start this, you firstly need to distribute the -3 to the "7x +6". Can you do that?

Answer 2

do i do -3 x 7 then -3 x 6?

Answer 3

my teacher was telling us to do 2x x 7x then -3 x 6 can you do that to?

Answer 4

I don't think so, PEMDAS tell us to multiply the -3 by the parenthesis firstly. Try that, and please restate it for me.

Answer 5

(-21+-18)?

Answer 6

Don't forget that it was "7x" before, not just "7".

Answer 7

oh -21x i mean

Answer 8

Yep! Now combine the "-21x" with the 2x. Then restate the entire equation as is for me.

Answer 9

191=-19x+6

Answer 10

Careful, you forgot to add in the 6 that had been multiplied by a three.

Answer 11

191=-19x+-18

Answer 12

Yep, so now do all you can to isolate the x. Restate each step for me please.

Answer 13

do i do 191-18

Answer 14

but do that to both sides witch would knock out the 18 completely which would leave 173=19x

Answer 15

No, recall that in order to move something being subtracted already from one side to the other, you have to add it, in order to cancel it out on the original side.

Answer 16

so 191+ -18

Answer 17

No, but you're close. You have to switch the sign when you add it. So instead it should be "191+18"

Answer 18

oh ok then that leaves 209=19x then do you divide both sides by 19?

Answer 19

Yep. And what do you get?

Answer 20

11=x

Answer 21

Wait, I'm sorry, but you should have had "-19x" on the right side. You restated it correctly right after you found it, but then both of us forgot about it. So, knowing that, What's your new answer?

Answer 22

-11=x

Answer 23

Yep! That's your final answer!

Answer 24

wow thank you you helped alot really :D

Answer 25

i have another one that im stumped on that has fractions do you think you could help me with that ? it seems like you get this really well

Answer 26

Fire away.

Answer 27

\[13=\frac{ 10x +17 }{ 9 }\]

Answer 28

Ok. Firstly, you need to remove the nine from the bottom. Know how you would? If not, then no problem, just say so.

Answer 29

all i can think of is to combine it with 17?

Answer 30

I'm afraid not, though good try. To eliminate the nine from the right side, you need to multiply it, as well as the left side, by something that would make the nine equal to one. So, think about this: What, when multiplied by nine, is equal to one?

Answer 31

im not sure

Answer 32

Ok, then I'll give you a general rule that will serve you throughout all of your math classes: When any number (let's call it "x") is multiplied by one over itself, it equals zero. The opposite is also true. Whenever any number, that is already the denominator of a fraction, is multiplied by itself over one, it equals one. Otherwise states as "x/1·1/x=1", and in reverse. So, given that, what times nine equals one?

Answer 33

x?

Answer 34

No, x in this context is just representative of any number. Perhaps an example would help here.