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Mathematics 9 Online
OpenStudy (anonymous):

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OpenStudy (anonymous):

Ratio test

OpenStudy (anonymous):

Which said it didn't work on it problem, because it says the series diverges? But I don't think it's supposed to diverge

OpenStudy (anonymous):

you testing lim abs ( a_(n+1) / a_n) ) = L n->inf if L < 0, the series converge if L > 0, the series diverge if L = 1, it's inconclusive did you try that?

OpenStudy (anonymous):

Yeah, and it came out as diverging for some reason

OpenStudy (anonymous):

you're only testing {[((-1)^(n))*((x^2)^(2n))]/(((2n)!))} not {[((-1)^(n))*((x^2)^(2n))]/(((2n)!))} - 1. -1 is not part of the sum

OpenStudy (anonymous):

Why is -1 not part of it?

OpenStudy (anonymous):

It is, I just may not have written it that way in the question, but it is part of the sum in the question.

OpenStudy (anonymous):

that is because {[((-1)^(n))*((x^2)^(2n))]/(((2n)!))} is the series for cos(x^2) only. Not cos(x^2) - 1 it's like this -1 + cos(x^2) -1 + sum{0->inf} {[((-1)^(n))*((x^2)^(2n))]/(((2n)!))},

OpenStudy (anonymous):

Oh, I see. So would the radius of convergence still be (-inf, +inf) then?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

What makes it be (-inf, +inf)? Is it proven by the ratio test or just because it converges or what?

OpenStudy (anonymous):

by ratio test

OpenStudy (anonymous):

okay, thank you

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