How do you graph the solution set of |-9x+2|-11>0?
Before graphing the solution set, you must solve the inequality for x using algebra. Do you know how to do that?
I dont know if its right but I got -13/9 and -1
Would you mind showing your steps?
sure for the one side i did -9x+2>11 subtract 2 to get -9x>9 then divide by -9 to get x<-1
for the other side i did -9x+2<-11 subtract 2 to get -9x<-13 divide by -9 to get x>-13/9
There are a couple particular rules you can use to help you: |a - b| = |b - a| So for the first step, I would rewrite: |-9x+2|-11>0 as |9x - 2| - 11 > 0 |9x - 2| > 11 Then split into two equations: 9x - 2 < -11 9x - 2 > 11 Then finish from there.
So the solution set is then -1, 13/9 instead of a -13/9?
You would have to graph the solution set. It's more than just a matter of posting numbers. You have to figure out where x is on the number line and graph that.
I guess what I am struggling with is graphing that on a real numbers line. I am thinking that I would shade in between the -1 and 13/9 but I am not positive. Sorry if that doesnt make sense.
If you solve the inequality algebraically, it will tell you which way to shade the graph. I notice that when you post your answers you avoid posting things like the variables and the inequality signs. Why?
If you're having trouble with that, I can help you.
No reasons why...just trying to answer fast :) When I solve for the equations you posted above I got x<-1 and x>13/9. So I put my "(" on my number line at -1 and then I have a "(" at 13/9 but am struggling with which way I need to draw/shade my lines.
Well, the < symbol means LESS THAN and the > symbol means GREATER THAN
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