Which is a solution of the absolute value function y = |x - 4| +2. A. (4, 2)<--- my answer B. (2, 4) C. (-4, 2) D. (2, -4)
how? can you show how you solved it?
do u divide
I'm assuming you mean "the vertex of the expression" ?
yes
|x - 4| <--- what value for "x" makes that = 0?
|x-4|+2
yes.... but just focusing on the absolute value expression what value of "x" would make the expression 0?
do you divide them and get 2
well...hmmm 2?
anyhow... well.. no you don't have to divide them.... you'd just get a value for "x" that makes the absolute expression =0 thus |x - 4| <--- what value for "x" makes that = 0?
oh okay -4
so will it be c
0-4=-4
let's see x = -4 |(-4)-4| = | -8| = 8 well. no dice on -4 so what do you think it'd be?
well i think this is confusing lol
heehe I didn't mean to say set x = 0 I meant to say a value for "x" that makes the expression in the bars =0 so say for example | x -25| if I set x = 25 then the expression becomes => | (25) - 25| => | 0| = 0 so x = 25 makes | x-25| to 0
25
for |x - 25| yes, that'd make it 0 how about for | x - 4 | ?
would it be x=4
yes
\(\bf |{\color{red}{ 4}} - 4| +{\color{red}{ 2}} \\ \quad \\ ({\color{red}{ 4,2}})\Leftarrow vertex\)
so my answer was right it was a
well, yes, but now you know how to obtain the vertex
well thanks you amazing
yw
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