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Chemistry 21 Online
OpenStudy (anonymous):

hey does anybody know the molarity of vinegar? i really will appreciate it

OpenStudy (4n1m0s1ty):

It depends on the percent by volume of acetic acid, but here's a calculation for a 5% vinegar solution: Assume we have 100 mL of vinegar, then 5 mL will be acetic acid, while 95 mL will be water. The density of acetic acid is 1.049 g/mL, so we end up with 5.245 g of acetic acid. To convert this to mols, we divide by the molecular weight of acetic acid, which is 60.05 g/mol to obtain 0.087 mols. Finally to get the molarity we just divide the number of mols of acetic acid by the total volume of the solution in L. 0.087 mols/0.1 L = 0.87 M which is the molarity of a 5% solution of acetic acid.

OpenStudy (anonymous):

go it!! thank you so much for that help! :)

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