Question

Show the sets to this mathway problem please. Will give out medals to all who attempt!!

Answer 1

show the steps*

Answer 2

ummm what is your question exactly?

Answer 3

show how the get the answer highlighted in red please

Answer 4

\[9x^2+8x=13\]
First we move the 13 over to the other side so it in the standard form of a quadratic equation
\[9x^2+8x-13=0\]
a=9, b=8, c=-13
Now we need to use the quadratic formula which is
\[\frac{-b\pm\sqrt{b^2-4*a*c}}{2a}\]
Begin plugging in your a,b and c

Answer 5

Then we can simplify and our answer will look pretty much identical to that one

Answer 6

Do you follow so far @vajhrbmn

Answer 7

no

Answer 8

Are you familiar with the quadratic formula?

Answer 9

here one sec

Answer 10

what is the entire question? usually it say. solve this equation using... so what was the full qauestion?

Answer 11

Firstly a quadratic equation in standard form is \(ax^2+bx+c=0\)
In this case our equation is \(9x^2+8x-13=0\)
So our a=9, b=8 and c=-13

Answer 12

Now we are given the quadratic formula that I have provided above and you basically plug in the values.

Answer 13

I can give the answer away but I do think it is imperative to use your brain

Answer 14

yeah i was plugging it into the quadratic forumula and geting -4/9

Answer 15

I just want to see the steps so I can get the answer in the future

Answer 16

ohhhh okkk ill do it for you

Answer 17

\[ \frac{ -8 \pm \sqrt{8^2-4(9)(-13)}}{2(9)}\]

Answer 18

\[\frac{-8 \pm \sqrt{64+468}}{18}\]
\[\frac{-8 \pm \sqrt{532}}{18}\]
\[\frac{-8 \pm \sqrt{2*2*133}}{18}\]
\[\frac{-8 \pm2 \sqrt{133}}{18}\]
\[\frac{2(-4 \pm \sqrt{133})}{18}\]
\[\frac{(-4 \pm \sqrt{133})}{9}\]