Question

The figure shows three right triangles. Triangles PQS, QRS, and PRQ are similar.

Theorem: If two triangles are similar, the corresponding sides are in proportion.

Figure shows triangle PQR with right angle at Q. Segment PQ is 4 and segment QR is 9. Point S is on segment PR and angles QSP and QSR are right angles.

Using the given theorem, which two statements help to prove that if segment PR is x, then x2 = 97?

Answer 1

http://assets.openstudy.com/updates/attachments/5029ce81e4b044f79e8f4df9-softballlover6655-1344917139145-cccccccccccccccccccccccccccccc.jpg

Answer 2

Using the given theorem, which two statements help to prove that if segment PR is x, then x2 = 97?

Segment PR x segment PS = 16
Segment PR x segment SR = 36

Segment PR x segment PS = 36
Segment PR x segment SR = 81

Segment PR x segment PS = 16
Segment PR x segment SR = 81

Segment PR x segment PS = 81
Segment PR x segment SR = 16

Answer 3

@phi @nikato @ganeshie8 Help please?

Answer 4

they want you to notice you can set up these ratios
\[ \frac{PS}{4}= \frac{4}{PR} \\ \frac{PR}{9}= \frac{9}{SR} \]

Answer 5

So would it be one of the last two

Answer 6

cross multiply those ratios to get the answers

Answer 7

I got the third one

Answer 8

@ninamarie @Destinymasha @Bethbarrson Help pleaseee

Answer 9

Yes. If you cross multiply @phi equations, you get the third choice