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Find the values of c and d that make the following function f(x)=\left\lbrace \begin{array}{cl} 2 x &\mbox{if } x<1\\ cx^2+d &\mbox{if } 1\le x <2\\ 5 x &\mbox{if } x\ge 2\\ \end{array}\right.
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A moment of reflection reveals that 2(1)=1^2 c+d 2^2 c +d = 5(2) so c+d=3 4 c + d =10 Solve for c and d
c+d =2 (Sorry)
\[ \left\{\left\{c\to \frac{8}{3},d\to -\frac{2}{3}\right\}\right\} \]
^hmm interesting
I wonder how you come to this conclusion 2(1)=1^2c+d
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because it was clearly stated that f(x)=2x when x<1 and need not to be equal to 1 please correct if I'm wrong
The limit from both sides should be equal
I cannot see any evidents saying the function is continuos
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