Ask
your own question, for FREE!
Mathematics
8 Online
Find the values of c and d that make the following function f(x)=\left\lbrace \begin{array}{cl} 2 x &\mbox{if } x<1\\ cx^2+d &\mbox{if } 1\le x <2\\ 5 x &\mbox{if } x\ge 2\\ \end{array}\right.
Still Need Help?
Join the QuestionCove community and study together with friends!
A moment of reflection reveals that 2(1)=1^2 c+d 2^2 c +d = 5(2) so c+d=3 4 c + d =10 Solve for c and d
c+d =2 (Sorry)
\[ \left\{\left\{c\to \frac{8}{3},d\to -\frac{2}{3}\right\}\right\} \]
^hmm interesting
I wonder how you come to this conclusion 2(1)=1^2c+d
Still Need Help?
Join the QuestionCove community and study together with friends!
because it was clearly stated that f(x)=2x when x<1 and need not to be equal to 1 please correct if I'm wrong
The limit from both sides should be equal
I cannot see any evidents saying the function is continuos
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
lovelove1700:
u00bfA quu00e9 hora es tu clase?Fill in the blanks Activity unlimited attempts left Completa.
glomore600:
find someone says that that one person your talking to doesn't really like you should I take their advice and leave or should I ask the person i'm talking t
Addif9911:
Him I dimmed the light that once felt mine, a glow I never meant to lose. I over-read the shadows, let voices crowd the room where only two hearts shouldu20
EdwinJsHispanic:
Poem to my mom who proved my point "You proved my point, I am a failure. but I kinda wish, you were my savior.
Wolfwoods:
The Modern Princess "you spoke so softly to me, held me close when no one else did, loved me in a way no one else dared to.
Wolfwoods:
The Pain Of Waiting "The short story would be that we fell in love, you left and I continued to wait for you.
notmeta:
balance the following equation - alumoinum chlorate --> alumninum chloride + oxyg
13 hours ago
0 Replies
0 Medals
16 hours ago
5 Replies
0 Medals
1 day ago
4 Replies
0 Medals
2 days ago
6 Replies
2 Medals
2 days ago
11 Replies
3 Medals
3 days ago
7 Replies
2 Medals
3 days ago
4 Replies
1 Medal