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Mathematics 15 Online
OpenStudy (anonymous):

MEDAL AND FAN WILL BE AWARDED!!! Does anyone know how to do this? Write an equation for a graph that is the set of all points in the plane that are equidistant from the given point and the given line. Focus(0,3) y=-1 The answer is: y=1/8x^2+1

zepdrix (zepdrix):

This is the definition of a parabola. The given line is what's called the "Directrix". Mmm I'm trying to remember how to relate the focus point to a parabola.. gimme few minutes.

OpenStudy (anonymous):

well isn't it the formula a= 1/4c?

OpenStudy (anonymous):

and isn't the focus c? but I just don't know how to get the answer that I'm suppose to get

OpenStudy (mathmale):

Romwill: zepdrix is correct when he says this: This is the definition of a parabola. The given line is what's called the "Directrix". I'd suggest we graph both the focus (0,3) and the given line y=-1.|dw:1393814513061:dw|

OpenStudy (mathmale):

Rule: the vertex of the parabola is exactly half-way between the focus and the directrix. Would one of you please find the vertex and graph it? Borrow my graph and add to it.

OpenStudy (anonymous):

well we just have to write an equation

OpenStudy (mathmale):

Yes, but to do that we have to know the location of the vertex. If you'd like to find the vertex without graphing it, fine. What are the x- and y-coordinates of the vertex?

OpenStudy (anonymous):

um.................... I'm not sure exactly

OpenStudy (mathmale):

that's why I've suggested drawing a graph and labeling the vertex.|dw:1393814887968:dw|

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