MEDAL AND FAN WILL BE AWARDED!!! Does anyone know how to do this? Write an equation for a graph that is the set of all points in the plane that are equidistant from the given point and the given line. Focus(0,3) y=-1 The answer is: y=1/8x^2+1
This is the definition of a parabola. The given line is what's called the "Directrix". Mmm I'm trying to remember how to relate the focus point to a parabola.. gimme few minutes.
well isn't it the formula a= 1/4c?
and isn't the focus c? but I just don't know how to get the answer that I'm suppose to get
Romwill: zepdrix is correct when he says this: This is the definition of a parabola. The given line is what's called the "Directrix". I'd suggest we graph both the focus (0,3) and the given line y=-1.|dw:1393814513061:dw|
Rule: the vertex of the parabola is exactly half-way between the focus and the directrix. Would one of you please find the vertex and graph it? Borrow my graph and add to it.
well we just have to write an equation
Yes, but to do that we have to know the location of the vertex. If you'd like to find the vertex without graphing it, fine. What are the x- and y-coordinates of the vertex?
um.................... I'm not sure exactly
that's why I've suggested drawing a graph and labeling the vertex.|dw:1393814887968:dw|
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