Help finding max and min of cosine function please. Question attached. I used wolfram alpha to verify the answer, I get the first part, but not the second.
The max comes out to be 6.2 + 12.4n, and the min = 12.4 n. I got the 6.2 part, but I have no idea where the 12.4 comes from
the maximum value of cosine is 1 and the minimum is -1 the maximum values of \(-28\cos(x)\) is \(28\) and the minimum value is \(-28\)
are you trying to find the maximum and minimum, or the \(t\) that gives it?
im trying to find the t that gives it
this is my work so far, not sure if I did it correct
max is when cosine is \(-1\) which will give you \(35+28=63\)' that occurs when \(\frac{\pi}{6.2}t=\pi\)
solve in one step, get \(t=\frac{6.2}{\pi}\times \pi=6.2\)
and of course min occurs when \(t=0\)
yes, I got that, but since it is periodical, wolfram said max occurs at 6.2+12.4n for max, and 12.4n for min. I am wondering where the 12.4 came from.
just as you said, it is periodic well not "periodical" but you have the right idea so max occurs if \(\frac{\pi}{6.2}=\pi,3\pi,5\pi,...\)
the first one gives \(t=6.2\) the second one gives \(3\times 6.2\) etc
ok I see thank you for your help.
notice that wolfram has for the max \(6.2+12.4n\) which is the same thing yw
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