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Mathematics 8 Online
OpenStudy (azureilai):

Help finding max and min of cosine function please. Question attached. I used wolfram alpha to verify the answer, I get the first part, but not the second.

OpenStudy (azureilai):

The max comes out to be 6.2 + 12.4n, and the min = 12.4 n. I got the 6.2 part, but I have no idea where the 12.4 comes from

OpenStudy (anonymous):

the maximum value of cosine is 1 and the minimum is -1 the maximum values of \(-28\cos(x)\) is \(28\) and the minimum value is \(-28\)

OpenStudy (anonymous):

are you trying to find the maximum and minimum, or the \(t\) that gives it?

OpenStudy (azureilai):

im trying to find the t that gives it

OpenStudy (azureilai):

this is my work so far, not sure if I did it correct

OpenStudy (anonymous):

max is when cosine is \(-1\) which will give you \(35+28=63\)' that occurs when \(\frac{\pi}{6.2}t=\pi\)

OpenStudy (anonymous):

solve in one step, get \(t=\frac{6.2}{\pi}\times \pi=6.2\)

OpenStudy (anonymous):

and of course min occurs when \(t=0\)

OpenStudy (azureilai):

yes, I got that, but since it is periodical, wolfram said max occurs at 6.2+12.4n for max, and 12.4n for min. I am wondering where the 12.4 came from.

OpenStudy (anonymous):

just as you said, it is periodic well not "periodical" but you have the right idea so max occurs if \(\frac{\pi}{6.2}=\pi,3\pi,5\pi,...\)

OpenStudy (anonymous):

the first one gives \(t=6.2\) the second one gives \(3\times 6.2\) etc

OpenStudy (azureilai):

ok I see thank you for your help.

OpenStudy (anonymous):

notice that wolfram has for the max \(6.2+12.4n\) which is the same thing yw

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