Question

Suppose f(π/3) = 5 and f '(π/3) = −7, and let g(x) = f(x) sin x and h(x) = (cos x)/f(x). Find the following. g'(pi/3), h'(pi/3)

Answer 1

Can you find \(g'(x)\) first?

Answer 2

If you can't, I will do it for you. Just tell me the truth.

Answer 3

well i have an answer, and it seems to match what wolframalpha gives as the derivative of the function, but the homework program is saying it is wrong.
it should be:
sinx*f'(x)+f(x)*cos(x) for g'(x)
(-cos(x)*f'(x)+f(x)*sin(x))/f^2(x) for h'(x)

Answer 4

so you plug in \(x=\pi/3\) for each one?

Answer 5

[(-7*sqrt{3}+5)/2]
[(-5*sqrt{3}+7)/50] ?

Answer 6

nevermind, got it