| 10-3|
-7
1/11 +(-5/7
@pammie39 10-3=7 Therefore, |10-3| also equals 7. The absolute value only tells you the distance of the number values from zero. Does that make sense? Basically, non negatives stay that way and negatives become positive
yes thanks
\(\Large\frac{1}{11}\) + (-\(\Large\frac{5}{7}\))
is that what you're asking?
yes
64/77
it will be postive since the postive is the bigger number
a good thing to do here is to make sure your denominators are equal, so 77 seems like a good place to be. \(\Large\frac{7}{77}\)+(-\(\Large\frac{55}{77}\)) then what you would do is add the numerators...and it would be negative, the reason is because 7-55 equals -48
remember the original order :)
so it will be negitive -64/77
Im not sure where you're getting 64, but its going to be -48/77
oh am adding it is -48/77
yes :)
oh and by the way, welcome to OpenStudy! :)
Thanks
-22 , 138 which one is the highest
138 would be, and the reason why is because it is not negative
ok thank you.
-4(a-9) using the distibutive property to slove
for problems like this, just addd the -4 to everything. -4a+36, since two negatives together make a positive alright, i have to go... see you!
ok
2t+2(1-2t)
\[19<6*x=11>4*x\]
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