Suppose in a proof of a summation formula 1+5+25+...+5^k -1=1/4 (5^k -1) by mathematical induction, you show the formula valid for L=1 and assume that it is valid for L=k. What is the next equation in the induction step of this proof? Please help! Will give best answer!
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OpenStudy (anonymous):
Is it a written response or multiple choice?
OpenStudy (anonymous):
BTW i like ur profile pic ;)
OpenStudy (anonymous):
multiple choice. im writing them out now
OpenStudy (anonymous):
k
OpenStudy (anonymous):
Where are the answers? :?
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OpenStudy (anonymous):
a 1+5+25+...+5^k-1 +5^k+1-1 = 1/4(5^k -1) +1/4(5^k+1 -1)
b 1+5+25+...+5^k +5^k+1 = 1/4(5^k -1)+5^k+1-1
OpenStudy (anonymous):
are there more?
OpenStudy (anonymous):
yes they just take forever to write so hold on
OpenStudy (anonymous):
ok lol
OpenStudy (anonymous):
c 1+5+25+...+5^k-1 +5^k+1-1 =1/4 (5^k -1) + 5^k+1-1
d 1+5+25+...+5^k-1 +5^k+1-1 = 1/4 (5^k+1 -1) + 5^k+1-1
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OpenStudy (anonymous):
ok the anser is c. i think im not so sure
OpenStudy (anonymous):
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OpenStudy (anonymous):
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OpenStudy (anonymous):
well because i just think so...
OpenStudy (anonymous):
im not going to become a fan, if you don't actually help me