Im still confused on how I find the solution to the system of equations with this problem... what about use a matrix to find the solution to te system of equations? -8x-9y=-16 6x-9y=-108 (-6,8) (6,8) (8,-6) (6,-8
You do not need to use matrices
i dont know the answer, or how to do it?
-8x-9y=-16 6x-9y=-108 Subtract the second from the first to get -14x =-16+108 -14 x =92 x=-46/7
Replace in one of equations and get y=160/21
All your choices are not correct or the equations are not typed correctly
use matrix to find the solution to the system of equations? -8x-8y=-16 6x-9y=-108
sorry i typed it wrong earlier
theres a matrix called A and is equal to (-8 -8) (6 -9) then you have B which is (-16) (-108)
first you find the determinant of the matrix A which is (-8)*(-9) - (-8)*6 and we'll call it detA
now to find x you need to replace the first column of A with the column-matrix B and also calculate its determinant (the product of the main diagonal minus the product of the secondary diagonal)
after youve done this, you simply do (the last determinant)/detA and you do the same for Y, only replacing the second column of A with the column-matrix B
thats all. It's called the Cramer rule
so whats the answer? (6,8)
thats left for you to do :)
not that hard really. simple multiplications
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