Question

More complicated quadratic question....
Solve. Explain your steps.
d^4+32=12d^2

Answer 1

Your picture... :/

Answer 2

This is the second time someone has commented on it in the last 10 minutes.....Its just a plant people lets be mature here.

Answer 3

first lets summon all variables on the same side of equation
d^4-12d^2+32=0

Answer 4

have you covered quadratic equations yet?

Answer 5

then to make it perfect square, we need to add 4 to 32 but not to distorb the original equation we need to subtract 4 as well

Answer 6

I do not know how to solve quadratic equations what so ever.... Im horrible at them.

Answer 7

d^4-12d^2+32+4-4=(d^4-12d^2+36)-4=0

Answer 8

we can rewrite the paranthesis like (d^2-6)^2

Answer 9

(d^2-6)^2-4=0 that is a perfect square as well

Answer 10

so (d^2-6-2)(d^2-6+2)=0
to organize (d^2-8)(d^2-4)=0
either variables have to be equal to zero

Answer 11

d^2-8=0 d=2\[\sqrt{2}\]
d^2-4=0 d=2

Answer 12

opps i mean \[2\sqrt{2}\]

Answer 13

did you understand???