Identify the center and the radius of the circle with equation x2 + (y - 5)2= 9
center (0, 5) and radius = 3
center (0, 5) and radius = 81
center (0, -5) and radius = 81
center (0, -5) and radius = 3
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OpenStudy (anonymous):
use equation of the circle again :)
OpenStudy (anonymous):
its
blah+blah=r^2
OpenStudy (anonymous):
if your
r^2=9 then r must be?
OpenStudy (anonymous):
3
OpenStudy (anonymous):
x2 + (y - 5)2= 9 is already in the equation
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OpenStudy (anonymous):
A or D :D
OpenStudy (jdoe0001):
\(\bf {\color{blue}{ 9\implies 3^2}}
\\ \quad \\ \quad \\
x^2 + (y - 5)2= 9\implies (x-0)^2 + (y - 5)2= 3^2\) what do you think?