Question

For questions 3-4 solve the equation using square roots.
A. x^2-81=0
B. 3x^2-147=0

Answer 1

will give medal

Answer 2

is A -9,9 and B no real number solutions

Answer 3

@phi @thomaster

Answer 4

for A, add 81 to both sides. you get x^2 = 81
take the sqr of both sides: x= ±sqr(81)= ±9

Answer 5

for B, first divide both sides (and all terms) by 3 to get
x^2- 49=0
now solve the same as in A

Answer 6

\[-\sqrt{9} \sqrt{9}\] is that right for A

Answer 7

and b -49 49

Answer 8

for A, it is \(\sqrt{81} \) which simplifies to +9 or -9

Answer 9

oh so i switched the numbers ok

Answer 10

for B
x^2- 49=0
add 49 to both sides
x^2 -49 + 49= 0+49
simplify (-49+49 on the left is 0)
x^2 = 49

now take the square root of both sides

Answer 11

7, -7 is the square root of 49, -49

Answer 12

yes

Answer 13

notice you run into trouble if the problem was
x^2 + 49 =0
we would add -49 to both sides:
x^2 + 49 - 49 = 0 - 49
simplify to
x^2 = -49 <-- TROUBLE sqr of a negative number