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√(e^(iπ/3)) Perform calculations and give answer in Cartesian form.
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\[\sqrt{e^{i\pi/3}}=\left(e^{i\pi/3}\right)^{1/2}=e^{i\frac{3\pi}{2}}=\cos\frac{3\pi}{2}+i\sin\frac{3\pi}{2}=\cdots\]
and thts it?
-i?
thts not the right answer though...
the answer is √3 / 2 +i/2 but idk how you got tht...
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Oh, sorry, my bad. I misread the question the second time around... \[\sqrt{e^{i\pi/3}}=\left(e^{i\pi/3}\right)^{1/2}=e^{i\color{red}{\frac{\pi}{6}}}=\cos\frac{\pi}{6}+i\sin\frac{\pi}{6}=\cdots\]
its e to the power i pi/3
kk well thnks anyways. just needed to check my work
Right, I just made a mistake with the fraction in the numerator. \(\dfrac{\pi}{3}\cdot\dfrac{1}{2}=\dfrac{\pi}{6}\).
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