Balance the following redox equation, identifying the element oxidized and the element reduced. Show all of the work used to solve the problem. Ag + CN- + O2 -> Ag(CN)2- + H2O Pretty lost on this question. This is how I've balanced the equation: 4H+ + Ag + 2CN- + O2 -> Ag(CN)2- + 2H2O And I don't really know which elements have been oxidized or reduced :/ please help
if someone could just tell me if i balanced it right, i think i could figure out which was oxidized and which was reduced by myself
Yes.
is Ag reduced?
no wait, O is reduced... so which is oxidized?
Remember: \(\sf \color{red}{OIL~RIG}\) \(\sf \color{red}{O}\)xidation \(\sf \color{red}{I}\)nvolves \(\sf \color{red}{L}\)oss of \(electrons\) \(\sf \color{red}{R}\)eduction \(\sf \color{red}{I}\)nvolves \(\sf \color{red}{G}\)ain of \(electrons\)
so O isn't reduced? i'm so confused. could you explain please? :/ i'm sorry
What's the oxidation of oxygen on the left?
0 and then on the right, it's -2. so that's why i thought it was reduced
So, it's gained electrons, meaning...
but i thought if the oxidation number decreased, then it was reduced
Join our real-time social learning platform and learn together with your friends!