Question

\[\frac{ x^3y^5 }{ x^2-5x-6 }\times \frac{ 2x^2-15x+18 }{ x^6y^5 }\]

Answer 1

some of the factor in the numerator of the first term cancel with factors in the denominator of the second

Answer 2

Try factoring out the polynomials and see if you can reduce it.

Answer 3

\[\frac{ x^3y^5 }{ (x-6)(x+1) }times \frac{ (2x-3)(x-6) }{ x^6y^5 }

Answer 4

\frac{ x^3y^5 }{ (x-6)(x+1) }times \frac{ (2x-3)(x-6) }{ x^6y^5 }

Answer 5

I need help

Answer 6

\[\frac{ x^3y^5 }{ (x-6)(x+1) }\times \frac{ (2x-3)(x-6) }{ x^6y^5 }\]

Answer 7

that's good factoring , now cancel common factors

Answer 8

I had thought it was \[\frac{ 2x-3 }{ x^3 }\]

but its incorrect

Answer 9

almost, one term is missing

Answer 10

in the denominator, you're missing the (x+1) it remains there.

Answer 11

Wow thank you for the help I've been trying to get help with this the whole day! what an overlook!