MEDAL!!! The following is an incomplete flow chart proving that the opposite angles of parallelogram JKLM are congruent:
Which statement and reason can be used to fill in the numbered blank spaces? ∠QJM ≅ ∠JKL Alternate Exterior Angles Theorem ∠JML ≅ ∠QJM Alternate Exterior Angles Theorem ∠QJM ≅ ∠JKL Alternate Interior Angles Theorem ∠JML ≅ ∠QJM Alternate Interior Angles Theorem
@wio can u help me?
@jigglypuff314 can u help me on this
@jigglypuff314 u there
The way I did it might be a bit confusing... the two steps after the blanks are <QJM = <LKJ by corresponding angles and <JML = LKJ by transitive property the clue is transitive the transitive property is if a=b and b=c then a=c they gave the last two parts "b=c then a=c" so the missing part should be "a=b" the two given parts have <LKJ in common and in the transitive property we can then match it up as "c" so then "b" = <QJM and "a" = <JML so for the missing part needed to make transitive property a =b you'll get <QJM = <JML and if you look at it that way, they are congruent by alternate interior angles
The third one
oh sorry, I was stating it based on letters. ∠QJM ≅ ∠JKL is not the same as <QJM = <JML it might help if I flipped it I meant <JML = <QJM
Yea I was gonna say it was the last one
thanks
glad I could help ^_^
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