Question

How do you integrate [(cosx)^4] (sinx)?

Answer 1

let
u=cosx
du=??

Answer 2

sinx

Answer 3

are you sure?

Answer 4

-sinx oops

Answer 5

-sinxdx
right
then what?

Answer 6

divide both sides of du=-sinxdx by -1 ?

Answer 7

ok
then?

Answer 8

i replace sinxdx with -du

Answer 9

hm i will solve it now

Answer 10

ok

Answer 11

i just didn't know i had to use u subsittuion

Answer 12

when do i use u substitution?

Answer 13

replace cos^4x
with u^4

Answer 14

do i differentiate u^4 and (cosx)^4

Answer 15

after substitution you have
\[\int\limits_{}^{}-u ^{4}du\]

Answer 16

should i use u=cosx or u^4 = (cosx)^4

Answer 17

both are the same

Answer 18

okay, i got what u wrote now

Answer 19

i took out the negative 1

Answer 20

ok

Answer 21

then i integrated and replaced the u with cosx

Answer 22

good

Answer 23

omg yay i got the right answer! ty!

Answer 24

have a good day

Answer 25

thankyou :)