Question

Urgent Help Please!!
Of 450 college students, 120 are enrolled in math, 225 are enrolled in English, and 55 are enrolled in both. If a student is selected at random, find the probability of the following.
(f) The student is not enrolled in English or is enrolled in mathematics.

Answer 1

first you would add the students enrolled in each of the subjects, or both 225=120=55=400
450-400=50
the probability is 50/400, or 1/8, or in decimal form is .125

Answer 2

The number of students not enrolled in English is 450 - 225 = 225.
Therefore the probability that a randomly selected student is not enrolled in English is
225/450.
The number of students enrolled in Math but not in English is 120 - 55 = 65.
Therefore the probability that a randomly selected student is enrolled in Math but not in English is 65/450.
the two events are mutually exclusive therefore the required probability is given by:
\[\frac{225}{450}+\frac{65}{450}=you\ can\ calculate\]

Answer 3

225+120+55=400*** by bad

Answer 4

I calculated 290/450=.644 but i still keep getting the answer wrong am i doing something wrong?

Answer 5

the question is worded weird, haha, is it trying to say the probability of somebody not enrolled in either subject/, bc that is what I solved for

Answer 6

I believe it is asking not enrolled in English but enrolled in math

Answer 7

oh okay, then I would say
120+55=175
175/450= appx. .389 percent of a chance

Answer 8

Alright Thank You =)