A 3.0-kg block sits on top of a 5.0-kg block which is on a horizontal surface. The 5.0-kg block is pulled to the right with a force F⃗ as shown in the figure(Figure 1) . The coefficient of static friction between all surfaces is 0.57 and the kinetic coefficient is 0.45.

A) What is the minimum value of F needed to move the two blocks?

B)If the force is 10% greater than your answer for (a), what is the acceleration of each block?

Question

A 3.0-kg block sits on top of a 5.0-kg block which is on a horizontal surface. The 5.0-kg block is pulled to the right with a force F⃗  as shown in the figure(Figure 1) . The coefficient of static friction between all surfaces is 0.57 and the kinetic coefficient is 0.45.

A) What is the minimum value of F needed to move the two blocks?

B)If the force is 10% greater than your answer for (a), what is the acceleration of each block?

anonymous · Answer

Figure 1: http://session.masteringphysics.com/problemAsset/1057164/5/GIANCOLI.ch05.p031.jpg

rajat97 · Answer

is it 79.8 N for part A???

rajat97 · Answer

@Hagopian13 ??

rajat97 · Answer

please let me know if it's correct
i gotta go
:)

anonymous · Answer

Oh sorry, I was elsewhere in my house.

anonymous · Answer

@rajat97
The answer is 78N when rounded, I put in 80N and go it correct. Could you please explain to me how you were able to get this answer when you get back? I have been working it for an hour today and an hour yesterday and am still stuck.

anonymous · Answer

I was able to figure out how to solve it, I forget to double force of friction in the small block because I did not substitute for T. Thanks again!

rajat97 · Answer

that's what i did:)

rajat97 · Answer

and yeah
i got this answer as i took g=10m/s^2