Question

I really don't understand.

Answer 1

I really need help on this one.

Answer 2

@ganeshie8 or @goformit100

Answer 3

Ignore the bottom part of the picture. (Bad editing)

Answer 4

a/4 = b/7

so a = ...?

and b = ...? @OrangeMaster

Answer 5

7a=4b?

Answer 6

almost perfect... bot thats 7b = ... and 4a = ...
we want a = ...? and b = ...?

Answer 7

sorry, flip that
but thats 7a = ... and 4b = ...

Answer 8

idk

Answer 9

so if 7a = 4b
a = 4b/7 or \[a = \frac 47 b \]
and
b = 7a/4 or \[b = \frac 74 a \]

Answer 10

so sub those exact fractions into your equation (a - b)/b

Answer 11

\[ \frac{ 4 }{ 7 }b-\frac{ 7 }{ 4 }a \div \frac{ 7 }{ 4 }a\]

Answer 12

almost perfect, remember to try to eliminate one of the variables though if possible
so lets keep the first a:

Answer 13

(a-b)/b can be written as

a/b - 1

from the things that are given to us we can conclude that a/b = 4/7

So

(a-b)/b = a/b - 1 = 4/7 - 1 = -3/7

Getting this? :)

Answer 14

I didn't type "idk". It happened when I accidentally hit back.

Answer 15

\[\huge \frac {a-\frac{ 7 }{ 4 }a} {\frac{ 7 }{ 4 }a}\]
\[\huge \frac {\frac {-3 }{ 4 }a} {\frac{ 7 }{ 4 }a}\]
\[\huge \frac {\frac {-3 }{ 4 }a}{a} \times \frac{ 4 }{ 7 }\]
\[\huge \frac {-3 }{ 4 } \times \frac{ 4 }{ 7 }\]
\[\huge \frac {-12 }{ 28 }\]
\[\huge \frac {-3 }{ 7}\]

Answer 16

OK, thank you @Jack1

Answer 17

hall good dude, yw