Question

5.The members of an organization are 10 men and 11 women. What is the probability that a committee of three selected at random is all female?

a-1/7
b-33/266
c-110/1,029
i got the first answer is that correct

Answer 1

hmm i doubt it

Answer 2

there are a couple of ways to do this
one is to find the number of ways to choose 3 out of a set of 21 for your denominator, i.e. compute
\[\binom{21}{3}\]

Answer 3

then for them all to be female, your numerator is \[\binom{11}{3}\]

Answer 4

the other way is to just count
probabilty first selected is female is
\[\frac{11}{21}\] then the probability that the second one is given that the first one is is
\[\frac{10}{20}\]and finally the probability that the third one is given the first two are is
\[\frac{9}{19}\]your answer is the product of those three numbers

Answer 5

i think i got it 33/266

Answer 6

i was right thanks