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Find the nth term of each geometric sequence. a = 4, n = 7, r = -3
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Ok so we know that a sequence has the form of \[\{ a, ar, ar^2, ar^3 ...\}\] We also know that the equation when finding a specific term of a geometric sequence is \[t_n=ar^{n-1}\] So plug in the values into your equation and you will get your answer
thank you :) so t^n=^4-^-1?
what?
4-1=3
\[t_7=4(-3)^{7-1}\]
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ohh sorry okay hold on
i typed all of that in my caculator and i got-8749
Okkk now (-3)^6=(-3)*(-3)*(-3)*(-3)*(-3)*(-3)=729 Since there are an even amount of negative symbols then and 2 negatives make a positive so (-3)^6=729
Then we multiply it by 4 and we get 2916
thank you!! you are a great teacher!
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