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Mathematics 13 Online
OpenStudy (anonymous):

For each sum find...

OpenStudy (anonymous):

OpenStudy (anonymous):

Hey @hartnn ! You got time?

OpenStudy (anonymous):

@bookworm00981 How bout you buddy? :)

OpenStudy (anonymous):

Ms. @Preetha ? Can you help me out with this?

OpenStudy (anonymous):

:)

OpenStudy (cwrw238):

for a) you have one term for n = 1 to 5 - this gives you the number of terms

OpenStudy (anonymous):

So there's 5 terms?

OpenStudy (cwrw238):

yes the first term can be found by plugging in n = 1 in the formula and last by doing the same with n=5

OpenStudy (anonymous):

So 3(5) + 1 right? And then that will equal 16

OpenStudy (cwrw238):

this is an arithmetic series thats the last term yes 16

OpenStudy (anonymous):

so the first term is 4?

OpenStudy (anonymous):

Since I plugged in n=1?

OpenStudy (cwrw238):

sum of n terms = (n/2)[a + l] where a = first term l = last term n = number of terms i in this case it is 5

OpenStudy (cwrw238):

yes

OpenStudy (anonymous):

Ok! So that means the sum is (5/2)[4+16] which equals 50!

OpenStudy (anonymous):

2.5 times 20 equals 50!

OpenStudy (cwrw238):

yup

OpenStudy (cwrw238):

pretty easy right?

OpenStudy (anonymous):

It sure was! :)

OpenStudy (anonymous):

Well thanks again! See ya!

OpenStudy (cwrw238):

bye

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