How to find the square root of a number? I really have a tough time solving Pythagorean Theorem questions because i can't square root a number at the end.. Is there a good and easy way to square root 1-3 digit numbers?
so the best way I know is to break it down into numbers you know the square of, if you can
A calculator.
ie \[\sqrt(396)=\sqrt(2*198)=\sqrt(4*99)\]
\[=\sqrt(4*3*33)=\sqrt(4*3*3*11)=2*3 * \sqrt(11)=6\sqrt(11)\]
This is also breaking it down into it's prime decomposition
as a side note
Make sense?
So if it were to ask me to find the square root of lets say 150, i would cut 150 in half which is 75? so Square root of 150 is 75 * 2
,,,,prime.....
Or would i go even further?
Until i get to a single or two digit number
Not really.
Until you get only prime numbers.
Are you interested in getting a decimal number, or a simplified expression? For a decimal number, use a calculator, or google, or wolframalpha.com or any number of websites. For a simplified expression, factor the quantity under the radical sign into its prime factors: 2,3,5,7,11,13,17,19,23,29,31,37,41,43, etc. 25=5*5 100 = 2*50=2*2*25=2*2*5*5 51 = 3*17 32=2*16=2*2*8=2*2*2*4=2*2*2*2*2 Now to simplify, remember that each pair of identical factors under the radical sign can be moved outside, and replaced by just one: \[\sqrt{150} = \sqrt{2*75} = \sqrt{2*3*25} = \sqrt{2*3*5*5} = 5\sqrt{2*3}=5\sqrt{6}\]
\[\sqrt{16} = \sqrt{2*2*2*2} = 2*2 = 4\]\[\sqrt{144} = \sqrt{2*72} = \sqrt{2*2*36} = \sqrt{2*2*2*18} \]\[=\sqrt{2*2*2*2*9} =2*2\sqrt{3*3} = 2*2*3 = 12\]
you want to go until you get a prime number
If you want more ammunition for tackling these problems, then you should 1) learn some of the divisibility rules. (This helps you to find factors) http://www.mathsisfun.com/divisibility-rules.html 2) learn as many of the primes as you can up through 100 http://www.factmonster.com/math/numbers/prime.html 3) Learn as many of the perfect squares as you can http://www.factmonster.com/ipka/A0875883.html and of course, know your multiplication table.
I am trying to find the length of the hypotenuse |dw:1393983237208:dw|
But they want the square root of 169 which is hard for me to give an answer.
so, that happens to be a special square
one that you have to memorize
169 is a number you might want to memorize.
try calculating the squares of the prime numbers like this 4,9,16,25... Does this come up?
your picture shows 15... do you mean 5 ? the triplet 3,4,5 is a right triangle almost as useful, is the 5,12,13 right triangle.
Yes sorry i meant 5
When they tell me to find the square root of 169 i usually start from the tens place and would multiply 11 * (1-12) then 12 * (1-12) and so forth
So i was wondering if there was a method of finding the square root easier.
The easiest way is to be familiar with the squares. you know 1*1, 2*2, and so on (hopefully up to 12*12= 144) but learn more! 13*13=169 notice that 13 is a prime number, so it would take awhile to figure out 13*13 is the answer...
I don't have a way other than memorization for 169, sorry :/
Are you saying the square root is always a prime number?
if you did not know 144 was 12*12 you could use the divisibility rules to break it into smaller numbers. for example: it ends in an even number, so 2 divides into. Even better, the last 2 digits (44) is divisible by 4, so the whole number is divisible by 4 to get 4* 36 now take the square root of 4 and of 36 to get 2*6=12 (the square root of 144) notice that 169 can not be divided by anything (except 13) so we can't do that trick)
no, but 169 happens to be, and the most efficient way when a number is not prime to get a simplified root is to break that number down into its prime decomposition. (the prime numbers multiplied together to get that number)
Ok well i guess it all makes more sense now, thank you both for your quick and great answers, i wish i could give you both medals haha..
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