Question

PLEASE HELP!! :(
Derivative of r = tan(x)sec(x)

a. = sec^2x(sin^3x+1)

b. = sec^3x(sin^2x +1)

c. = sin^3 x (sec^2x +1)

d. = sec^3x (sinx+1)

Answer 1

so, are you familiar with the product rule?

Answer 2

\[\frac{ d }{dx }\left( uv \right)=uv'+vu'\]

Answer 3

yes! i know the product rule.

Answer 4

so, what you are going to do is apply it, then simplify

Answer 5

so why don't you try the first step

Answer 6

\[\frac{ d }{ dx }\tan x=\sec ^2x\]
\[\frac{ d }{ dx }\left( \sec x \right)=\sec x~ \tan x\]

Answer 7

what i got when i used the product rule was sec(x)(tan^2(x)+sec^2(x))

Answer 8

but i could not figure out how the sin(x) got into the equation...

Answer 9

ok good, so do you know any identities that use tan^2x or sec^2 x?