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This is the midpoint formula: \[(\frac{x _{1}+x _{2}}{2},\frac{y _{1}+y _{2}}2)\]
x_1 and x_2 are the x coordinates of the two points. y_1 and y_2 are the y coordinates of the two points.
I will demonstrate with # 6
The two points are: (12,-7) and (-4,7) so: \[(\frac{12+(-4)}{2},\frac{-7+7}{2}) =( \frac{8}{2},\frac{0}{2})=(4,0)\] And that is the midpoint.
No. In #7 the midpoint is given.
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One point is (6,3) and the midpoint is (-3,4) \[(\frac{6+x}{2},\frac{3+y}{2})=(-3,4)\]
\[\frac{6+x}{2}=-3\] \[\frac{3+y}{2}=4\]
That is the midpoint formula with the variables in a different place.
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