You have 1.366 x 102 mL of oxygen gas (O2) at 7.55 x 102 mm of Hg and 70 oC. What is the mass of the sample in milligrams?
Isn't this a case of PV=nRT?
Yes
Then just plug in and solve for n
I forget the unit requirements. Are the units right or does something have to be converted?
I think it's alright in this case. Is the answer 386.89?
Did you convert the temp to degrees Kelvin?
No. Hold on
770.1?
I forget what the ideal gas constant is.
I'm not sure either.
Well then how did you solve it?
It's not right.
I only have 30 minutes left to answer 10 questions, I'd appreciate rapid help!
What you are taking a timed test?
It's not a test, just an online assignment and the turn in time cuts off in 30 minutes so I'm pretty pressured right now.
62.36367=R if volume is in L, temp in degrees Kelvin and pressure in mm of Hg
Is R the mass?
R is the ideal gas constant
n is the number of moles.
The question was dismissed because I accidently reset it. Now: You have 4.108 x 102 mL of oxygen gas (O2) at 7.19 x 102 mm of Hg and 23 oC. What is the mass of the sample in milligrams?
That is exactly the same problem with different numbers.
I still don't know how to set it up! Do this one for me so I can follow the steps please?
Change the mL to liters
If a gas has a volume of 7.1 L at a temp of 22 Degrees Celsius and a pressure of 3.1 atm, how many moles of gas are present?
R=82.05736 Now since you have changed the units the constant has changed. And you have to change the L to ml
7.1L= 7100 mL 22 degrees Celsius = 295 degrees Kelvin so: \[3.1(7100)=n(82.05736)(295)\]
Solve for n
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