Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

I need help on a question!!! someone please helppp:/!! My math teacher is foreign so he has a strong accent and I does not really know how to explain well!! I am stuck on a certain section of probability...please help!!

OpenStudy (anonymous):

What is the question?

OpenStudy (anonymous):

A shelf in the STAPLE store contains 50 colored ink cartridges for a particular ink-jet printer. Eight of the cartridges are defective. If a customer selects 5 cartridges at random from the shelf; in how many ways the customer can select under the following situations: a) Exactly two cartridges are defective? b)at most one cartridge is defective?

OpenStudy (anonymous):

Ok Im back

OpenStudy (anonymous):

What grade are you in?

OpenStudy (anonymous):

ahhh you are offline. Message me if you come back

OpenStudy (anonymous):

freshmen and im here

OpenStudy (anonymous):

Ok I am assuming that every cartridge is unique and has its own identity, I am not sure if we should be solving like this buttt this what I am assuming There are 8 defective and 42 in working order inkjets #1)Selects 2 defective inkjets and 3 Regular inkjets soo For the first one we choose is defective and there are 5 choices The second one we choose is also defective but there are only 4 choices since we already picked one defective so there are only 4 left Now The third choice is in working order and there are 42 choices to choose from The fifth selection is also in working order but there are only 41 choices since one regular inkjet has been already taken off the shelf The last selection is in working order too but there are only 40 choices since 2 regular inkjets have been taken of the shelf So there are 5*4*42*41*40 options in how the customer can select cartridges where 2 are defective and 3 are in working order

OpenStudy (anonymous):

so this means what exactly?

OpenStudy (anonymous):

ughhh

OpenStudy (anonymous):

DO you want the answer or the explanation cuz I can just give you the answer if you would like

OpenStudy (anonymous):

No explanation is needed so I can understand...

OpenStudy (anonymous):

So I multiply those numbers out right?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

I wanna give you an easier example so you can understand this topic but give me a sec

OpenStudy (anonymous):

ok thank you

OpenStudy (anonymous):

Ok lets say there are 5 people in the room and only 3 chairs

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

So how many different ways can we have people sitting on a chair. Each chair is specific

OpenStudy (anonymous):

So on chair #1 There are 5 people so there is a possibility of 5 different people sitting on that chair Do you agree with this?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!