Question

f =1/(2pi squareroot (L*C))

Solve for L

Answer 1

I got L = 1/C*4pi^2*f^2 is this correct?

Answer 2

\[f _{0}=\frac{ 1 }{ 2\pi \sqrt{LC} }\]

Answer 3

^ original question

Answer 4

\[L=\frac{ 1 }{ C4\pi^2f _{0}^2 }\]

My answer

Answer 5

Yes. You did correctly

Answer 6

@whpalmer4

Answer 7

Looks good to me.