Question

A triangular playground has angles with measures in the ratio 8 : 4 : 3. What is the measure of the smallest angle?

Answer 1

let the angles be 8x, 4x, 3x
\[\huge 8x+ 4x+ 3x=180^0\]
\[\huge 15x=180^0 \rightarrow x = \frac{180^0}{15} = 12^0\]
Smallest angle = 3x = 3 * 12 = 36 degrees

Answer 2

Thank you! :)

Answer 3

Can you help me with a few more? I was absent.

Answer 4

Sure, go ahead..

Answer 5

Write an in slope-intercept form of the line through point P(-8,6) with slope 4.

Answer 6

Ok, pls wait..

Answer 7

Given: \[\huge (x_1, y_1) = (-8,6) \rightarrow x_1=-8, y_1= 6\] Slope m= 4The eq. of line in slope-point form is given as:
\[\huge (y- y_1) = m((x-x_1)\]
Substituting the above values in the eq we find:

\[\huge (y- 6) = 4[x-(-8)] \rightarrow (y- 6) = 4(x+8)\]
\[\huge \rightarrow (y- 6) = 4(x+8) \rightarrow y-6= 4x- 32\]
\[\huge \rightarrow y= 4x- 32+6\rightarrow y= 4x- 26\]

Answer 8

@BlveXO

Answer 9

Okay, just one more. :P

Answer 10

You are a tremendous help.

Answer 11

What is an equation for the line that passes through points (2,-7) and (4,3)?

Answer 12

Since line is passing through points (2,-7) and (4,3), so eq of line in 2-point form is given as:
Here: (x1, y1) =(2,-7) & (x2, y2) = (4,3)
\[\huge {y-y_1} = m(x-x_1)\]
\[ \huge \rightarrow {y-y_1} = \frac{(y_2-y_1)}{(x_2-x_1)}(x-x_1)\]
Now susstituting the above values we find:
\[ \huge \rightarrow {y-(-7)} = \frac{3-(-7)}{4-2}(x-2)\]
\[ \huge \rightarrow {y+7} = \frac{3+7}{2}(x-2)\]
\[ \huge \rightarrow {y+7} = \frac{10}{2}(x-2)\]
\[ \huge \rightarrow {y+7} = 5(x-2)\]
\[ \huge \rightarrow {y+7} = 5x-10\]
\[ \huge \rightarrow {y} = 5x-10-7\]
\[ \huge \rightarrow y= 5x-17\] is the required eq of the line.

Answer 13

@BlveXO

Answer 14

Okay, thank you.! :)