Question

SOMEBODY PLEASE HELP ME! An isosceles triangle is drawn so that it has the same area as the above square (i.e. x), and with two sides that are equal to the square root of x (henceforth dubbed y). What is the length of the third side?

Answer 1

@karategirl2002

Answer 2

can u help me plz

Answer 3

yeah

Answer 4

ok thx

Answer 5

NP

Answer 6

well if it is the same # all the way around then it would be the same but do you have a graph or the triangle

Answer 7

it doesnt show

Answer 8

its very hard and i really dont get it

Answer 9

I think I get it

Answer 10

ok can u tell me @BlackLabel and @karategirl2002

Answer 11

Just to confirm the square has an area of x?

Answer 12

i guess i really dont get it

Answer 13

ok um i show a pic

Answer 14

ok thx @karategirl2002

Answer 15

use that pic okay

Answer 16

ok thx

Answer 17

@karategirl2002

Answer 18

im right here

Answer 19

oh srry

Answer 20

it okay

Answer 21

You didnt finish solving the question ....
Im slightly confused by the wording of this question. It seems there should be a picture of a square.

Answer 22

You totally missed out an important part of the question in order to solve it.

You are given a triangle that has sides of 66cm, 73cm, and 94cm. One of the angles is right-angled (meaning that it is possible by trial and error to calculate what each of the angles are). Inside this triangle is a square, so that three corners are in contact with the lines bounding the triangle. One of the sides or the square, which we shall now dub z, is also tangent to a circle, with a radius such that the centre of the circle lies along the side of the triangle with length 73cm. You are also given a regular octagon, which you are told is the same area as the total are of the circle and triangle if they are taken together (i.e. the overlapping area is not counted twice), and one side of this octagon forms another side of equal length belonging to a second square. The area of this square is dubbed x.