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OpenStudy (anonymous):
Let F=2xi+2yj+z2k . Let S be the portion of the double cone x^2+y^2=z^2 lying between the planes z=−2 and z=1. Orient S by outward pointing normals (where "inward" means towards the z-axis). Then integral of S FdS=
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OpenStudy (anonymous):
2xi+2yj+z^2k
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